Ÿþ 0 5

Ÿþr – Ÿþ5

05:31

Ÿþ 5 @ 0 – Ÿþ 0 @ 5 =

02:05

Ÿþb – Ÿþ" 0 = 5 F

08:28

Ÿþ 0 = 5 B 8 – Ÿþ

03:16

Ÿþ . – Ÿþ" 0 = 5 F

07:10

Ÿþ 0 ; 5 @ 8 9 – Ÿþ! 2 5 B

00:48

Ÿþ ! – Ÿþ 0 5 ; L 8

03:36

Ÿþl – Ÿþ" @ 5 H

03:49

Ÿþ ( B 0 5 B – Ÿþ" K

03:00

– Ÿþ 0 = 5 B 8

03:05

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